Distance from Sokolow Podlaski to North Babylon
The shortest distance (air line) between Sokolow Podlaski and North Babylon is 4,272.15 mi (6,875.36 km).
How far is Sokolow Podlaski from North Babylon
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 00:02 (21.08.2025)
North Babylon is located in New York, United States within 40° 43' 53.04" N -74° 40' 30.72" W (40.7314, -73.3248) coordinates. The local time in North Babylon is 18:02 (20.08.2025)
The calculated flying distance from North Babylon to North Babylon is 4,272.15 miles which is equal to 6,875.36 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
North Babylon, New York, United States