Distance from Sokolow Podlaski to New Brunswick
The shortest distance (air line) between Sokolow Podlaski and New Brunswick is 4,324.73 mi (6,959.99 km).
How far is Sokolow Podlaski from New Brunswick
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 21:25 (20.08.2025)
New Brunswick is located in New Jersey, United States within 40° 29' 13.2" N -75° 33' 18" W (40.4870, -74.4450) coordinates. The local time in New Brunswick is 15:25 (20.08.2025)
The calculated flying distance from New Brunswick to New Brunswick is 4,324.73 miles which is equal to 6,959.99 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
New Brunswick, New Jersey, United States