Distance from Sokolow Podlaski to Montgomery
The shortest distance (air line) between Sokolow Podlaski and Montgomery is 5,176.24 mi (8,330.35 km).
How far is Sokolow Podlaski from Montgomery
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 09:50 (20.08.2025)
Montgomery is located in Alabama, United States within 32° 20' 53.52" N -87° 43' 59.52" W (32.3482, -86.2668) coordinates. The local time in Montgomery is 02:50 (20.08.2025)
The calculated flying distance from Montgomery to Montgomery is 5,176.24 miles which is equal to 8,330.35 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Montgomery, Alabama, United States