Distance from Sokolow Podlaski to Lexington
The shortest distance (air line) between Sokolow Podlaski and Lexington is 4,802.48 mi (7,728.85 km).
How far is Sokolow Podlaski from Lexington
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 10:59 (19.08.2025)
Lexington is located in Kentucky, United States within 38° 2' 32.28" N -85° 32' 28.68" W (38.0423, -84.4587) coordinates. The local time in Lexington is 04:59 (19.08.2025)
The calculated flying distance from Lexington to Lexington is 4,802.48 miles which is equal to 7,728.85 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Lexington, Kentucky, United States