Distance from Sokolow Podlaski to Las Cruces
The shortest distance (air line) between Sokolow Podlaski and Las Cruces is 5,826.11 mi (9,376.22 km).
How far is Sokolow Podlaski from Las Cruces
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 10:25 (19.08.2025)
Las Cruces is located in New Mexico, United States within 32° 19' 35.4" N -107° 12' 38.52" W (32.3265, -106.7893) coordinates. The local time in Las Cruces is 02:25 (19.08.2025)
The calculated flying distance from Las Cruces to Las Cruces is 5,826.11 miles which is equal to 9,376.22 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Las Cruces, New Mexico, United States