Distance from Sokolow Podlaski to Langley Park
The shortest distance (air line) between Sokolow Podlaski and Langley Park is 4,491.93 mi (7,229.07 km).
How far is Sokolow Podlaski from Langley Park
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 04:20 (19.08.2025)
Langley Park is located in Maryland, United States within 38° 59' 22.92" N -77° 1' 9.12" W (38.9897, -76.9808) coordinates. The local time in Langley Park is 22:20 (18.08.2025)
The calculated flying distance from Langley Park to Langley Park is 4,491.93 miles which is equal to 7,229.07 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Langley Park, Maryland, United States