Distance from Sokolow Podlaski to Jacksonville Beach
The shortest distance (air line) between Sokolow Podlaski and Jacksonville Beach is 5,115.18 mi (8,232.09 km).
How far is Sokolow Podlaski from Jacksonville Beach
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 03:06 (01.09.2025)
Jacksonville Beach is located in Florida, United States within 30° 16' 41.52" N -82° 35' 43.8" W (30.2782, -81.4045) coordinates. The local time in Jacksonville Beach is 21:06 (31.08.2025)
The calculated flying distance from Jacksonville Beach to Jacksonville Beach is 5,115.18 miles which is equal to 8,232.09 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Jacksonville Beach, Florida, United States