Distance from Sokolow Podlaski to Griffin
The shortest distance (air line) between Sokolow Podlaski and Griffin is 5,057.07 mi (8,138.57 km).
How far is Sokolow Podlaski from Griffin
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 14:20 (17.08.2025)
Griffin is located in Georgia, United States within 33° 14' 30.48" N -85° 43' 30.72" W (33.2418, -84.2748) coordinates. The local time in Griffin is 08:20 (17.08.2025)
The calculated flying distance from Griffin to Griffin is 5,057.07 miles which is equal to 8,138.57 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Griffin, Georgia, United States