Distance from Sokolow Podlaski to Farmington Hills
The shortest distance (air line) between Sokolow Podlaski and Farmington Hills is 4,528.99 mi (7,288.71 km).
How far is Sokolow Podlaski from Farmington Hills
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 13:04 (16.08.2025)
Farmington Hills is located in Michigan, United States within 42° 29' 9.6" N -84° 37' 22.44" W (42.4860, -83.3771) coordinates. The local time in Farmington Hills is 07:04 (16.08.2025)
The calculated flying distance from Farmington Hills to Farmington Hills is 4,528.99 miles which is equal to 7,288.71 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Farmington Hills, Michigan, United States