Distance from Sokolow Podlaski to Farmington
The shortest distance (air line) between Sokolow Podlaski and Farmington is 5,594.02 mi (9,002.71 km).
How far is Sokolow Podlaski from Farmington
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 19:18 (15.08.2025)
Farmington is located in New Mexico, United States within 36° 45' 19.8" N -109° 49' 3.72" W (36.7555, -108.1823) coordinates. The local time in Farmington is 11:18 (15.08.2025)
The calculated flying distance from Farmington to Farmington is 5,594.02 miles which is equal to 9,002.71 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Farmington, New Mexico, United States