Distance from Sokolow Podlaski to Essex Junction
The shortest distance (air line) between Sokolow Podlaski and Essex Junction is 4,078.82 mi (6,564.23 km).
How far is Sokolow Podlaski from Essex Junction
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 09:41 (16.08.2025)
Essex Junction is located in Vermont, United States within 44° 29' 24.72" N -74° 53' 9.24" W (44.4902, -73.1141) coordinates. The local time in Essex Junction is 03:41 (16.08.2025)
The calculated flying distance from Essex Junction to Essex Junction is 4,078.82 miles which is equal to 6,564.23 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Essex Junction, Vermont, United States