Distance from Sokolow Podlaski to East Patchogue
The shortest distance (air line) between Sokolow Podlaski and East Patchogue is 4,257.81 mi (6,852.29 km).
How far is Sokolow Podlaski from East Patchogue
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 10:24 (15.08.2025)
East Patchogue is located in New York, United States within 40° 46' 13.44" N -73° 1' 5.88" W (40.7704, -72.9817) coordinates. The local time in East Patchogue is 04:24 (15.08.2025)
The calculated flying distance from East Patchogue to East Patchogue is 4,257.81 miles which is equal to 6,852.29 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
East Patchogue, New York, United States