Distance from Sokolow Podlaski to Dix Hills
The shortest distance (air line) between Sokolow Podlaski and Dix Hills is 4,269.01 mi (6,870.30 km).
How far is Sokolow Podlaski from Dix Hills
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 11:24 (15.08.2025)
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 05:24 (15.08.2025)
The calculated flying distance from Dix Hills to Dix Hills is 4,269.01 miles which is equal to 6,870.30 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Dix Hills, New York, United States