Distance from Sokolow Podlaski to Dickinson
The shortest distance (air line) between Sokolow Podlaski and Dickinson is 4,849.20 mi (7,804.04 km).
How far is Sokolow Podlaski from Dickinson
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 07:07 (15.08.2025)
Dickinson is located in North Dakota, United States within 46° 53' 30.48" N -103° 12' 27" W (46.8918, -102.7925) coordinates. The local time in Dickinson is 23:07 (14.08.2025)
The calculated flying distance from Dickinson to Dickinson is 4,849.20 miles which is equal to 7,804.04 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Dickinson, North Dakota, United States