Distance from Sokolow Podlaski to Chestnut Ridge
The shortest distance (air line) between Sokolow Podlaski and Chestnut Ridge is 4,280.76 mi (6,889.22 km).
How far is Sokolow Podlaski from Chestnut Ridge
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 03:00 (16.08.2025)
Chestnut Ridge is located in New York, United States within 41° 4' 58.44" N -75° 56' 41.64" W (41.0829, -74.0551) coordinates. The local time in Chestnut Ridge is 21:00 (15.08.2025)
The calculated flying distance from Chestnut Ridge to Chestnut Ridge is 4,280.76 miles which is equal to 6,889.22 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Chestnut Ridge, New York, United States