Distance from Sokolow Podlaski to Chesapeake
The shortest distance (air line) between Sokolow Podlaski and Chesapeake is 4,587.25 mi (7,382.47 km).
How far is Sokolow Podlaski from Chesapeake
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 03:08 (16.08.2025)
Chesapeake is located in Virginia, United States within 36° 40' 40.08" N -77° 41' 51.72" W (36.6778, -76.3023) coordinates. The local time in Chesapeake is 21:08 (15.08.2025)
The calculated flying distance from Chesapeake to Chesapeake is 4,587.25 miles which is equal to 7,382.47 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Chesapeake, Virginia, United States