Distance from Sokolow Podlaski to Charlottesville
The shortest distance (air line) between Sokolow Podlaski and Charlottesville is 4,595.02 mi (7,394.98 km).
How far is Sokolow Podlaski from Charlottesville
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 21:29 (15.08.2025)
Charlottesville is located in Virginia, United States within 38° 2' 15" N -79° 30' 52.2" W (38.0375, -78.4855) coordinates. The local time in Charlottesville is 15:29 (15.08.2025)
The calculated flying distance from Charlottesville to Charlottesville is 4,595.02 miles which is equal to 7,394.98 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Charlottesville, Virginia, United States