Distance from Sokolow Podlaski to Chapel Hill
The shortest distance (air line) between Sokolow Podlaski and Chapel Hill is 4,725.83 mi (7,605.49 km).
How far is Sokolow Podlaski from Chapel Hill
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 23:22 (15.08.2025)
Chapel Hill is located in North Carolina, United States within 35° 55' 37.56" N -80° 57' 39.24" W (35.9271, -79.0391) coordinates. The local time in Chapel Hill is 17:22 (15.08.2025)
The calculated flying distance from Chapel Hill to Chapel Hill is 4,725.83 miles which is equal to 7,605.49 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Chapel Hill, North Carolina, United States