Distance from Sokolow Podlaski to Burnsville
The shortest distance (air line) between Sokolow Podlaski and Burnsville is 4,712.75 mi (7,584.44 km).
How far is Sokolow Podlaski from Burnsville
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 09:28 (13.08.2025)
Burnsville is located in Minnesota, United States within 44° 45' 53.28" N -94° 43' 14.52" W (44.7648, -93.2793) coordinates. The local time in Burnsville is 02:28 (13.08.2025)
The calculated flying distance from Burnsville to Burnsville is 4,712.75 miles which is equal to 7,584.44 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Burnsville, Minnesota, United States