Distance from Sokolow Podlaski to Brunswick
The shortest distance (air line) between Sokolow Podlaski and Brunswick is 4,542.40 mi (7,310.28 km).
How far is Sokolow Podlaski from Brunswick
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 18:17 (12.08.2025)
Brunswick is located in Ohio, United States within 41° 14' 47.4" N -82° 10' 48.72" W (41.2465, -81.8198) coordinates. The local time in Brunswick is 12:17 (12.08.2025)
The calculated flying distance from Brunswick to Brunswick is 4,542.40 miles which is equal to 7,310.28 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Brunswick, Ohio, United States