Distance from Sokolow Podlaski to Bronx
The shortest distance (air line) between Sokolow Podlaski and Bronx is 4,285.68 mi (6,897.13 km).
How far is Sokolow Podlaski from Bronx
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 19:43 (12.08.2025)
Bronx is located in New York, United States within 40° 51' 0.36" N -74° 8' 1.68" W (40.8501, -73.8662) coordinates. The local time in Bronx is 13:43 (12.08.2025)
The calculated flying distance from Bronx to Bronx is 4,285.68 miles which is equal to 6,897.13 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Bronx, New York, United States