Distance from Sokolow Podlaski to Blunsdon Saint Andrew
The shortest distance (air line) between Sokolow Podlaski and Blunsdon Saint Andrew is 1,019.23 mi (1,640.30 km).
How far is Sokolow Podlaski from Blunsdon Saint Andrew
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 09:52 (04.08.2025)
Blunsdon Saint Andrew is located in Swindon, United Kingdom within 51° 36' 36" N -2° 12' 36" W (51.6100, -1.7900) coordinates. The local time in Blunsdon Saint Andrew is 08:52 (04.08.2025)
The calculated flying distance from Blunsdon Saint Andrew to Blunsdon Saint Andrew is 1,019.23 miles which is equal to 1,640.30 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Blunsdon Saint Andrew, Swindon, United Kingdom