Distance from Sokolow Podlaski to Bloomsburg
The shortest distance (air line) between Sokolow Podlaski and Bloomsburg is 4,370.06 mi (7,032.94 km).
How far is Sokolow Podlaski from Bloomsburg
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 06:55 (12.08.2025)
Bloomsburg is located in Pennsylvania, United States within 41° 0' 9.72" N -77° 32' 38.04" W (41.0027, -76.4561) coordinates. The local time in Bloomsburg is 00:55 (12.08.2025)
The calculated flying distance from Bloomsburg to Bloomsburg is 4,370.06 miles which is equal to 7,032.94 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Bloomsburg, Pennsylvania, United States