Distance from Sokolow Podlaski to Bloomington
The shortest distance (air line) between Sokolow Podlaski and Bloomington is 4,818.47 mi (7,754.59 km).
How far is Sokolow Podlaski from Bloomington
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 06:51 (12.08.2025)
Bloomington is located in Illinois, United States within 40° 28' 32.52" N -89° 1' 46.92" W (40.4757, -88.9703) coordinates. The local time in Bloomington is 23:51 (11.08.2025)
The calculated flying distance from Bloomington to Bloomington is 4,818.47 miles which is equal to 7,754.59 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Bloomington, Illinois, United States