Distance from Sokolow Podlaski to Austintown
The shortest distance (air line) between Sokolow Podlaski and Austintown is 4,513.85 mi (7,264.33 km).
How far is Sokolow Podlaski from Austintown
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 23:40 (11.08.2025)
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 17:40 (11.08.2025)
The calculated flying distance from Austintown to Austintown is 4,513.85 miles which is equal to 7,264.33 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Austintown, Ohio, United States