Distance from Sokolow Podlaski to Ashington
The shortest distance (air line) between Sokolow Podlaski and Ashington is 985.86 mi (1,586.58 km).
How far is Sokolow Podlaski from Ashington
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 17:15 (05.08.2025)
Ashington is located in Northumberland, United Kingdom within 55° 10' 51.6" N -2° 25' 55.2" W (55.1810, -1.5680) coordinates. The local time in Ashington is 16:15 (05.08.2025)
The calculated flying distance from Ashington to Ashington is 985.86 miles which is equal to 1,586.58 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Ashington, Northumberland, United Kingdom