Distance from Sokolow Podlaski to Armthorpe
The shortest distance (air line) between Sokolow Podlaski and Armthorpe is 968.47 mi (1,558.60 km).
How far is Sokolow Podlaski from Armthorpe
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 20:25 (03.08.2025)
Armthorpe is located in Barnsley; Doncaster and Rotherham, United Kingdom within 53° 32' 6.72" N -2° 56' 52.08" W (53.5352, -1.0522) coordinates. The local time in Armthorpe is 19:25 (03.08.2025)
The calculated flying distance from Armthorpe to Armthorpe is 968.47 miles which is equal to 1,558.60 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Armthorpe, Barnsley; Doncaster and Rotherham, United Kingdom