Distance from Sokolow Podlaski to Arecibo
The shortest distance (air line) between Sokolow Podlaski and Arecibo is 5,173.28 mi (8,325.59 km).
How far is Sokolow Podlaski from Arecibo
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 06:50 (12.08.2025)
Arecibo is located in Puerto Rico, United States within 18° 26' 56.76" N -67° 15' 40.68" W (18.4491, -66.7387) coordinates. The local time in Arecibo is 01:50 (12.08.2025)
The calculated flying distance from Arecibo to Arecibo is 5,173.28 miles which is equal to 8,325.59 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Arecibo, Puerto Rico, United States