Distance from Sokolow Podlaski to Arbutus
The shortest distance (air line) between Sokolow Podlaski and Arbutus is 4,468.58 mi (7,191.49 km).
How far is Sokolow Podlaski from Arbutus
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 18:53 (11.08.2025)
Arbutus is located in Maryland, United States within 39° 14' 34.08" N -77° 18' 28.08" W (39.2428, -76.6922) coordinates. The local time in Arbutus is 12:53 (11.08.2025)
The calculated flying distance from Arbutus to Arbutus is 4,468.58 miles which is equal to 7,191.49 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Arbutus, Maryland, United States