Distance from Sokolow Podlaski to Alexander City
The shortest distance (air line) between Sokolow Podlaski and Alexander City is 5,132.92 mi (8,260.64 km).
How far is Sokolow Podlaski from Alexander City
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 20:25 (11.08.2025)
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 13:25 (11.08.2025)
The calculated flying distance from Alexander City to Alexander City is 5,132.92 miles which is equal to 8,260.64 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Alexander City, Alabama, United States