Distance from Sokolow Podlaski to Albany
The shortest distance (air line) between Sokolow Podlaski and Albany is 4,192.60 mi (6,747.35 km).
How far is Sokolow Podlaski from Albany
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 22:11 (11.08.2025)
Albany is located in New York, United States within 42° 39' 59.04" N -74° 12' 4.68" W (42.6664, -73.7987) coordinates. The local time in Albany is 16:11 (11.08.2025)
The calculated flying distance from Albany to Albany is 4,192.60 miles which is equal to 6,747.35 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Albany, New York, United States