Distance from Sokolow Podlaski to Abbots Langley
The shortest distance (air line) between Sokolow Podlaski and Abbots Langley is 960.34 mi (1,545.51 km).
How far is Sokolow Podlaski from Abbots Langley
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 21:55 (03.08.2025)
Abbots Langley is located in Hertfordshire, United Kingdom within 51° 42' 3.6" N -1° 35' 2.4" W (51.7010, -0.4160) coordinates. The local time in Abbots Langley is 20:55 (03.08.2025)
The calculated flying distance from Abbots Langley to Abbots Langley is 960.34 miles which is equal to 1,545.51 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Abbots Langley, Hertfordshire, United Kingdom