Distance from Snyder to Aleksandrow Kujawski
The shortest distance (air line) between Snyder and Aleksandrow Kujawski is 5,501.74 mi (8,854.19 km).
How far is Snyder from Aleksandrow Kujawski
Snyder is located in Texas, United States within 32° 42' 47.88" N -101° 5' 18.24" W (32.7133, -100.9116) coordinates. The local time in Snyder is 14:54 (12.11.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 21:54 (12.11.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 5,501.74 miles which is equal to 8,854.19 km.
Related Distances from Snyder
Aleksandrow Kujawski, Włocławski, Poland