Distance from Sioux Falls to Kampenhout
The shortest distance (air line) between Sioux Falls and Kampenhout is 4,390.31 mi (7,065.52 km).
How far is Sioux Falls from Kampenhout
Sioux Falls is located in South Dakota, United States within 43° 32' 22.56" N -97° 16' 8.04" W (43.5396, -96.7311) coordinates. The local time in Sioux Falls is 21:42 (02.08.2025)
Kampenhout is located in Arr. Halle-Vilvoorde, Belgium within 50° 56' 28.68" N 4° 32' 58.56" E (50.9413, 4.5496) coordinates. The local time in Kampenhout is 04:42 (03.08.2025)
The calculated flying distance from Kampenhout to Kampenhout is 4,390.31 miles which is equal to 7,065.52 km.
Sioux Falls, South Dakota, United States
Related Distances from Sioux Falls
Kampenhout, Arr. Halle-Vilvoorde, Belgium