Distance from Sicklerville to Janow Lubelski
The shortest distance (air line) between Sicklerville and Janow Lubelski is 4,449.52 mi (7,160.82 km).
How far is Sicklerville from Janow Lubelski
Sicklerville is located in New Jersey, United States within 39° 44' 42.72" N -75° 0' 23.76" W (39.7452, -74.9934) coordinates. The local time in Sicklerville is 04:04 (11.11.2025)
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 10:04 (11.11.2025)
The calculated flying distance from Janow Lubelski to Janow Lubelski is 4,449.52 miles which is equal to 7,160.82 km.
Sicklerville, New Jersey, United States
Related Distances from Sicklerville
Janow Lubelski, Puławski, Poland