Distance from Sicklerville to Boguszow-Gorce
The shortest distance (air line) between Sicklerville and Boguszow-Gorce is 4,213.30 mi (6,780.66 km).
How far is Sicklerville from Boguszow-Gorce
Sicklerville is located in New Jersey, United States within 39° 44' 42.72" N -75° 0' 23.76" W (39.7452, -74.9934) coordinates. The local time in Sicklerville is 04:48 (11.11.2025)
Boguszow-Gorce is located in Wałbrzyski, Poland within 50° 46' 0.12" N 16° 11' 60" E (50.7667, 16.2000) coordinates. The local time in Boguszow-Gorce is 10:48 (11.11.2025)
The calculated flying distance from Boguszow-Gorce to Boguszow-Gorce is 4,213.30 miles which is equal to 6,780.66 km.
Sicklerville, New Jersey, United States
Related Distances from Sicklerville
Boguszow-Gorce, Wałbrzyski, Poland