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      Distance from Shenandoah to Chateauneuf-les-Martigues

      The shortest distance (air line) between Shenandoah and Chateauneuf-les-Martigues is 5,093.81 mi (8,197.70 km).

      How far is Shenandoah from Chateauneuf-les-Martigues

      Shenandoah is located in Louisiana, United States within 30° 24' 6.84" N -92° 59' 52.8" W (30.4019, -91.0020) coordinates. The local time in Shenandoah is 07:07 (08.08.2025)

      Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 14:07 (08.08.2025)

      The calculated flying distance from Chateauneuf-les-Martigues to Chateauneuf-les-Martigues is 5,093.81 miles which is equal to 8,197.70 km.

      Shenandoah, Louisiana, United States

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      Chateauneuf-les-Martigues, Bouches-du-Rhône, France

      Related Distances to Chateauneuf-les-Martigues