Distance from Shakopee to Sint-Andries
The shortest distance (air line) between Shakopee and Sint-Andries is 4,157.89 mi (6,691.47 km).
How far is Shakopee from Sint-Andries
Shakopee is located in Minnesota, United States within 44° 46' 28.2" N -94° 31' 22.08" W (44.7745, -93.4772) coordinates. The local time in Shakopee is 22:35 (01.08.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 05:35 (02.08.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 4,157.89 miles which is equal to 6,691.47 km.
Shakopee, Minnesota, United States
Related Distances from Shakopee
Sint-Andries, Arr. Brugge, Belgium