Distance from Shakopee to Janow Lubelski
The shortest distance (air line) between Shakopee and Janow Lubelski is 4,807.61 mi (7,737.11 km).
How far is Shakopee from Janow Lubelski
Shakopee is located in Minnesota, United States within 44° 46' 28.2" N -94° 31' 22.08" W (44.7745, -93.4772) coordinates. The local time in Shakopee is 05:26 (30.08.2025)
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 12:26 (30.08.2025)
The calculated flying distance from Janow Lubelski to Janow Lubelski is 4,807.61 miles which is equal to 7,737.11 km.
Shakopee, Minnesota, United States
Related Distances from Shakopee
Janow Lubelski, Puławski, Poland