Distance from Shakopee to Aleksandrow Lodzki
The shortest distance (air line) between Shakopee and Aleksandrow Lodzki is 4,659.32 mi (7,498.45 km).
How far is Shakopee from Aleksandrow Lodzki
Shakopee is located in Minnesota, United States within 44° 46' 28.2" N -94° 31' 22.08" W (44.7745, -93.4772) coordinates. The local time in Shakopee is 21:16 (29.08.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 04:16 (30.08.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,659.32 miles which is equal to 7,498.45 km.
Shakopee, Minnesota, United States
Related Distances from Shakopee
Aleksandrow Lodzki, Łódzki, Poland