Distance from Seymour to Oudenburg
The shortest distance (air line) between Seymour and Oudenburg is 4,149.17 mi (6,677.44 km).
How far is Seymour from Oudenburg
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 05:58 (03.08.2025)
Oudenburg is located in Arr. Oostende, Belgium within 51° 10' 59.88" N 3° 0' 0" E (51.1833, 3.0000) coordinates. The local time in Oudenburg is 11:58 (03.08.2025)
The calculated flying distance from Oudenburg to Oudenburg is 4,149.17 miles which is equal to 6,677.44 km.
Seymour, Indiana, United States
Related Distances from Seymour
Oudenburg, Arr. Oostende, Belgium