Distance from Severn to Montechiarugolo
The shortest distance (air line) between Severn and Montechiarugolo is 4,274.13 mi (6,878.54 km).
How far is Severn from Montechiarugolo
Severn is located in Maryland, United States within 39° 8' 7.8" N -77° 18' 15.84" W (39.1355, -76.6956) coordinates. The local time in Severn is 14:16 (30.08.2025)
Montechiarugolo is located in Parma, Italy within 44° 41' 36.24" N 10° 25' 20.64" E (44.6934, 10.4224) coordinates. The local time in Montechiarugolo is 20:16 (30.08.2025)
The calculated flying distance from Montechiarugolo to Montechiarugolo is 4,274.13 miles which is equal to 6,878.54 km.
Severn, Maryland, United States