Distance from Severn to Diepenbeek
The shortest distance (air line) between Severn and Diepenbeek is 3,879.82 mi (6,243.97 km).
How far is Severn from Diepenbeek
Severn is located in Maryland, United States within 39° 8' 7.8" N -77° 18' 15.84" W (39.1355, -76.6956) coordinates. The local time in Severn is 19:26 (30.07.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 01:26 (31.07.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 3,879.82 miles which is equal to 6,243.97 km.
Severn, Maryland, United States
Related Distances from Severn
Diepenbeek, Arr. Hasselt, Belgium