Distance from Seven Hills to Koekelberg
The shortest distance (air line) between Seven Hills and Koekelberg is 3,933.10 mi (6,329.72 km).
How far is Seven Hills from Koekelberg
Seven Hills is located in Ohio, United States within 41° 22' 49.08" N -82° 19' 35.04" W (41.3803, -81.6736) coordinates. The local time in Seven Hills is 23:16 (08.10.2025)
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 05:16 (09.10.2025)
The calculated flying distance from Koekelberg to Koekelberg is 3,933.10 miles which is equal to 6,329.72 km.
Seven Hills, Ohio, United States
Related Distances from Seven Hills
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium