Distance from Seven Hills to Diepenbeek
The shortest distance (air line) between Seven Hills and Diepenbeek is 3,973.93 mi (6,395.43 km).
How far is Seven Hills from Diepenbeek
Seven Hills is located in Ohio, United States within 41° 22' 49.08" N -82° 19' 35.04" W (41.3803, -81.6736) coordinates. The local time in Seven Hills is 02:42 (01.08.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 08:42 (01.08.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 3,973.93 miles which is equal to 6,395.43 km.
Seven Hills, Ohio, United States
Related Distances from Seven Hills
Diepenbeek, Arr. Hasselt, Belgium