Distance from Sentrupert to Aleksandrow Kujawski
The shortest distance (air line) between Sentrupert and Aleksandrow Kujawski is 503.32 mi (810.02 km).
How far is Sentrupert from Aleksandrow Kujawski
Sentrupert is located in Jugovzhodna Slovenija, Slovenia within 45° 58' 36.84" N 15° 5' 22.92" E (45.9769, 15.0897) coordinates. The local time in Sentrupert is 08:23 (17.11.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 08:23 (17.11.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 503.32 miles which is equal to 810.02 km.
Sentrupert, Jugovzhodna Slovenija, Slovenia
Related Distances from Sentrupert
Aleksandrow Kujawski, Włocławski, Poland