Distance from Seguin to Fontainebleau
The shortest distance (air line) between Seguin and Fontainebleau is 5,167.21 mi (8,315.82 km).
How far is Seguin from Fontainebleau
Seguin is located in Texas, United States within 29° 35' 20.76" N -98° 1' 56.64" W (29.5891, -97.9676) coordinates. The local time in Seguin is 06:58 (09.08.2025)
Fontainebleau is located in Seine-et-Marne, France within 48° 24' 32.04" N 2° 42' 6.12" E (48.4089, 2.7017) coordinates. The local time in Fontainebleau is 13:58 (09.08.2025)
The calculated flying distance from Fontainebleau to Fontainebleau is 5,167.21 miles which is equal to 8,315.82 km.
Related Distances from Seguin
Fontainebleau, Seine-et-Marne, France