Distance from Sedro-Woolley to Aleksandrovac
The shortest distance (air line) between Sedro-Woolley and Aleksandrovac is 5,703.40 mi (9,178.74 km).
How far is Sedro-Woolley from Aleksandrovac
Sedro-Woolley is located in Washington, United States within 48° 30' 40.32" N -123° 46' 4.44" W (48.5112, -122.2321) coordinates. The local time in Sedro-Woolley is 21:47 (13.11.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 06:47 (14.11.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 5,703.40 miles which is equal to 9,178.74 km.
Sedro-Woolley, Washington, United States
Related Distances from Sedro-Woolley
Aleksandrovac, Rasinska oblast, Serbia