Distance from Secaucus to Zaandijk
The shortest distance (air line) between Secaucus and Zaandijk is 3,635.96 mi (5,851.51 km).
How far is Secaucus from Zaandijk
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 13:59 (11.11.2025)
Zaandijk is located in Zaanstreek, Netherlands within 52° 28' 0.12" N 4° 47' 60" E (52.4667, 4.8000) coordinates. The local time in Zaandijk is 19:59 (11.11.2025)
The calculated flying distance from Zaandijk to Zaandijk is 3,635.96 miles which is equal to 5,851.51 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Zaandijk, Zaanstreek, Netherlands