Distance from Secaucus to Woensdrecht
The shortest distance (air line) between Secaucus and Woensdrecht is 3,643.41 mi (5,863.51 km).
How far is Secaucus from Woensdrecht
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 21:13 (11.11.2025)
Woensdrecht is located in West-Noord-Brabant, Netherlands within 51° 25' 0.12" N 4° 19' 59.88" E (51.4167, 4.3333) coordinates. The local time in Woensdrecht is 03:13 (12.11.2025)
The calculated flying distance from Woensdrecht to Woensdrecht is 3,643.41 miles which is equal to 5,863.51 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Woensdrecht, West-Noord-Brabant, Netherlands